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Given a tree where every right node is a leaf, meaning that it can only extend on the left side, invert it such that the leftmost node is now the root, and all of the previous left nodes are now on the right side. The former right nodes will be on the left side.
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Software Engineer

Interviewed at LinkedIn

3.8
Oct 28, 2015

Given a tree where every right node is a leaf, meaning that it can only extend on the left side, invert it such that the leftmost node is now the root, and all of the previous left nodes are now on the right side. The former right nodes will be on the left side.

A couple tricky questions. One required writing a modified binary search, the other dealt with data structures and how to efficiently check if a given set of numbers contained two numbers summing to some other number x.
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Software Engineer Intern

Interviewed at LinkedIn

3.8
Feb 8, 2013

A couple tricky questions. One required writing a modified binary search, the other dealt with data structures and how to efficiently check if a given set of numbers contained two numbers summing to some other number x.

2. /** * A tournament tree is a binary tree * where the parent is the minimum of the two children. * Given a tournament tree find the second minimum value in the tree. * A node in the tree will always have 2 or 0 children. * Also all leaves will have distinct and unique values. * 2 * / \ * 2 3 * / \ | \ * 4 2 5 3 * * In this given tree the answer is 3. */ class Node { Integer value; Node left, right; Node(Integer value, Node left, Node right) { this.value = value; this.left = left; this.right = right; } } class Solution { /** * This should return the second minimum * int value in the given tournament tree */ public static Integer secondMin(Node root) { } }
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Senior Software Engineer

Interviewed at LinkedIn

3.8
Apr 5, 2017

2. /** * A tournament tree is a binary tree * where the parent is the minimum of the two children. * Given a tournament tree find the second minimum value in the tree. * A node in the tree will always have 2 or 0 children. * Also all leaves will have distinct and unique values. * 2 * / \ * 2 3 * / \ | \ * 4 2 5 3 * * In this given tree the answer is 3. */ class Node { Integer value; Node left, right; Node(Integer value, Node left, Node right) { this.value = value; this.left = left; this.right = right; } } class Solution { /** * This should return the second minimum * int value in the given tournament tree */ public static Integer secondMin(Node root) { } }

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