Developer Interview Questions

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First Round: Write a pattern 1: Should accept only odd numbers numbers only except 2: Pattern should be fully Dynamic for n =1 @@@@@ * ** *** **** ***** ****** ***** **** *** ** * @@@@@ Second Round:n=6 * ** *** **** ****** ****** ***** **** *** ** *
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Python Developer

Interviewed at WebKul

4.1
May 26, 2019

First Round: Write a pattern 1: Should accept only odd numbers numbers only except 2: Pattern should be fully Dynamic for n =1 @@@@@ * ** *** **** ***** ****** ***** **** *** ** * @@@@@ Second Round:n=6 * ** *** **** ****** ****** ***** **** *** ** *

// Given var endorsements = [ { skill: 'css', user: 'Bill' }, { skill: 'javascript', user: 'Chad' }, { skill: 'javascript', user: 'Bill' }, { skill: 'css', user: 'Sue' }, { skill: 'javascript', user: 'Sue' }, { skill: 'html', user: 'Sue' } ]; getSkills = (endorsements) => { // Result // [ // { skill: 'javascript', user: ['Chad', 'Bill', 'Sue'], count: 3 }, // { skill: 'css', user: ['Sue', 'Bill'], count: 2 }, // { skill: 'html', user: ['Sue'], count: 1 } // ]; } see this image: http://i.imgur.com/UIeB3n4.png
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Front End Developer

Interviewed at LinkedIn

3.8
Jan 8, 2019

// Given var endorsements = [ { skill: 'css', user: 'Bill' }, { skill: 'javascript', user: 'Chad' }, { skill: 'javascript', user: 'Bill' }, { skill: 'css', user: 'Sue' }, { skill: 'javascript', user: 'Sue' }, { skill: 'html', user: 'Sue' } ]; getSkills = (endorsements) => { // Result // [ // { skill: 'javascript', user: ['Chad', 'Bill', 'Sue'], count: 3 }, // { skill: 'css', user: ['Sue', 'Bill'], count: 2 }, // { skill: 'html', user: ['Sue'], count: 1 } // ]; } see this image: http://i.imgur.com/UIeB3n4.png

1. Given a 3 array like below NSArray *a = [1,3,4,5]; NSArray *b = [-1,3,0,9]; NSArray *c = [0,31,32,22,6]; Find the elements from the three array which existing in atleast 2 arrays. Eg: [3, 0] Because 3 is presented in array a, b and 0 is presented in array b, c respectively. -(NSArray)find2ElementsAtleastPresentIn2Arrays:(NSArray*)aList b::(NSArray*)bList c::(NSArray*)cList{ // -- your code here. }
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IOS Developer

Interviewed at Booking.com

4.1
Aug 13, 2015

1. Given a 3 array like below NSArray *a = [1,3,4,5]; NSArray *b = [-1,3,0,9]; NSArray *c = [0,31,32,22,6]; Find the elements from the three array which existing in atleast 2 arrays. Eg: [3, 0] Because 3 is presented in array a, b and 0 is presented in array b, c respectively. -(NSArray)find2ElementsAtleastPresentIn2Arrays:(NSArray*)aList b::(NSArray*)bList c::(NSArray*)cList{ // -- your code here. }

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